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: $B : 2 $B : F. $B2=3XJ*@-CM$N7W;;K!(B


G. $BC10L$N49;;Ey$N7W;;(B

G.1 $B:.9gHf$H%b%kHf(B($BJ,05(B)$B$H$N49;;<0(B

$B:.9g5$BN$r9M$($k(B. $B4%[email protected],$NE:$(;z$r(B $d$ $B$H$7(B, $B<>[email protected],$NE:$(;z$r(B $v$ $B$H(B $B$9$k(B. $B$3$3$G$OG$0U$N<>[email protected],5$BN(B($BE:$(;z(B $x$)$B$N:.9gHf(B, $BJ,05$r5a$a$k(B.

$B:.9gHf(B $q_{x}$ $B$rJ,05(B $p_{x}$ $B$GI=8=$9$k$H(B,

$\displaystyle q_{x}$ $\textstyle =$ $\displaystyle \frac{\rho_{x}}{\rho_{d}}$  
  $\textstyle =$ $\displaystyle \left(
\frac{R_{d} T}{p} \frac{1/M_{d} + \sum_{v} q_{v}/M_{v}}{1/M_{d}}
\right)
\frac{p_{x}}{R_{x}T}$  
  $\textstyle =$ $\displaystyle \frac{p_{x}}{p} M_{x} (1/M_{d} + \sum_{v} q_{v}/M_{v})$  
$\displaystyle q_{x} \left(1 - \frac{p_{x}}{p} \right)$ $\textstyle =$ $\displaystyle \frac{p_{x}}{p} M_{x} (1/M_{d} + \sum_{v \neq x} q_{v}/M_{v})$  
$\displaystyle q_{x}$ $\textstyle =$ $\displaystyle \frac{p_{x}}{p}\frac{ M_{x} (1/M_{d} + \sum_{v \neq x} q_{v}/M_{v}) }
{\left(1 - \frac{p_{x}}{p} \right) }$  
$\displaystyle q_{x}$ $\textstyle =$ $\displaystyle \frac{ p_{x} M_{x} (1/M_{d} + \sum_{v \neq x} q_{v}/M_{v}) }{p - p_{x}}$  
$\displaystyle q_{x}$ $\textstyle =$ $\displaystyle \frac{ p_{x} M_{x} (1/M_{d} + \sum_{v \neq x} q_{v}/M_{v}) }
{p_{0} \pi^{{c_{p}}_{d}/R_{d}} - p_{x}}$ (G.1)

$B$H$J$j(B, $B%b%kHf(B $x_{x}$ $B$GI=8=$9$k$H(B,
$\displaystyle q_{x} =
\frac{ x_{x} M_{x} (1/M_{d} + \sum_{v \neq x} q_{v}/M_{v})}{ 1 - x_{x} }$     (G.2)

$B$H$J$k(B.

$B0lJ}$G(B, $BJ,05(B $p_{x}$ $B$r:.9gHf(B $q_{x}$ $B$GI=8=$9$k$H(B,

$\displaystyle p_{x}$ $\textstyle =$ $\displaystyle \frac{q_{x} p}{M_{x} (1/M_{d} + \sum_{v} q_{v}/M_{v})}$  
$\displaystyle p_{x}$ $\textstyle =$ $\displaystyle \frac{q_{x}p_{0} \pi^{{c_{p}}_{d}/R_{d}} }{M_{x} (1/M_{d} + \sum_{v} q_{v}/M_{v})}$ (G.3)

$B$G$"$j(B, $B%b%kHf(B $x_{x}$ $B$GI=8=$9$k$H(B,
$\displaystyle x_{x}$ $\textstyle =$ $\displaystyle \frac{q_{x}}{M_{x} (1/M_{d} + \sum_{v} q_{v}/M_{v})}$ (G.4)

$B$G$"$k(B.


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: $B : 2 $B : F. $B2=3XJ*@-CM$N7W;;K!(B
Odaka Masatsugu $BJ?@.(B18$BG/(B9$B7n(B23$BF|(B